b selling a bucket for rupees 67.50 a shopkeeper loses 10% .How much percent would he gain or loss by selling it for rupees 82.50
Answers
Answered by
60
SP = 67.5
LOSS = 10%
CP = 67.5 * 100/90
= 75
now,
new sp = 82.5
gain = sp- cp
82.5 - 75
7.5
gain% = gain/CP * 100
7.5/75 *100
10%
LOSS = 10%
CP = 67.5 * 100/90
= 75
now,
new sp = 82.5
gain = sp- cp
82.5 - 75
7.5
gain% = gain/CP * 100
7.5/75 *100
10%
vidit1007:
from where you got 90/100
Answered by
9
Dear Student,
● Answer -
Seller will gain 10 % profit when he sells bucket 82.50 %.
● Explaination -
# Given -
SP1 = 67.50 %
Loss1 = 10 %
# Solution -
Let CP be cost price of the bucket.
SP1 = CP × (100 - loss1) / 100
67.50 = CP × (100-10)/100
67.50 = CP × 90/100
CP = 67.50 × 100/90
CP = 75 Rs
When SP is 82.50 Rs, there will be profit.
SP2 = CP × (100 + profit) / 100
82.50 = 75 × (100 + profit) / 100
100 + profit = 82.50 × 100 / 75
100 + profit = 110
Profit = 110 - 100
Profit = 10 %
Hence, seller will gain 10 % profit when he sells bucket 82.50 %.
Thanks dear. Hope this helps you...
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