Math, asked by suvarshagoud, 1 year ago

(b) Show that (a - b) + (b - c) + (c - a)} = 3 (a - b) (b - c) (c-a)
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Answers

Answered by rishu6845
3

Answer:

(a-b) ^3+(b-c)^3+(c-a) ^3

let

p=(a-b) q=(b-c) r=(c-a)

p+q+r=a-b+b-c+c-a=0

so

p^3+q^3+r^3=3pqr

(a-b) ^3+(b-c)^3+(c-a) ^3=3(a-b)(b-c) (c- a)

Answered by Anonymous
0

Answer:

Step-by-step explanation:

a+b = 8

b+c = 10

c+a = 12

a = 8-b

b = 10-c

c = 12-a

a+b+c ==> (8-b) + (10-c) + (12-a)

20-b-c-a

20 - (A+B+C)

A+B+C = 20

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