(b) Show that (a - b) + (b - c) + (c - a)} = 3 (a - b) (b - c) (c-a)
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Answers
Answered by
3
Answer:
(a-b) ^3+(b-c)^3+(c-a) ^3
let
p=(a-b) q=(b-c) r=(c-a)
p+q+r=a-b+b-c+c-a=0
so
p^3+q^3+r^3=3pqr
(a-b) ^3+(b-c)^3+(c-a) ^3=3(a-b)(b-c) (c- a)
Answered by
0
Answer:
Step-by-step explanation:
a+b = 8
b+c = 10
c+a = 12
a = 8-b
b = 10-c
c = 12-a
a+b+c ==> (8-b) + (10-c) + (12-a)
20-b-c-a
20 - (A+B+C)
A+B+C = 20
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