b.
Simplify following logic expression using Boolea
i) AB + A'C = (A + C) + (A' +B)
D
DO
Answers
Answered by
0
Answer:
(A + B) * (A’ + C)
→ AA’ + AC + A’B + BC
→ 0 + AC + A’B + BC
→ AC + CB + A’B
By the consensus theorem:
xy + yz + x’z = xy + x’z
Let A = x, B = z, C = y
→ AC + CB + A’B = xy + yz + x’z
→ AC + A’B = xy + x’z
Therefore, (A + B) * (A’ + C) = AC + A’B
Step-by-step explanation:
(A + B) * (A’ + C)
→ AA’ + AC + A’B + BC
→ 0 + AC + A’B + BC
→ AC + CB + A’B
By the consensus theorem:
xy + yz + x’z = xy + x’z
Let A = x, B = z, C = y
→ AC + CB + A’B = xy + yz + x’z
→ AC + A’B = xy + x’z
Therefore, (A + B) * (A’ + C) = AC + A’B
Similar questions