Math, asked by ashimghimire008, 2 months ago

(b)
sin A + cos A
sec A + cosec A=
sin A. Cos A​

Answers

Answered by bhadanapardeep856
0

Answer:

L.H.S=(cscA−sinA)(secA−cosA)

=(

sinA

1

−sinA)(

cosA

1

−cosA) where cscA=

sinA

1

and secA=

cosA

1

=(

sinA

1−sin

2

A

)(

cosA

1−cos

2

A

)

=(

sinA

cos

2

A

)(

cosA

sin

2

A

) where 1−sin

2

A=cos

2

A and 1−cos

2

A=sin

2

A

=sinAcosA

R.H.S=

tanA+cotA

1

=

cosA

sinA

+

sinA

cosA

1

=

sinAcosA

sin

2

A+cos

2

A

1

=sinAcosA where sin

2

A+cos

2

A=1

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