(b)
sin A + cos A
sec A + cosec A=
sin A. Cos A
Answers
Answered by
0
Answer:
L.H.S=(cscA−sinA)(secA−cosA)
=(
sinA
1
−sinA)(
cosA
1
−cosA) where cscA=
sinA
1
and secA=
cosA
1
=(
sinA
1−sin
2
A
)(
cosA
1−cos
2
A
)
=(
sinA
cos
2
A
)(
cosA
sin
2
A
) where 1−sin
2
A=cos
2
A and 1−cos
2
A=sin
2
A
=sinAcosA
R.H.S=
tanA+cotA
1
=
cosA
sinA
+
sinA
cosA
1
=
sinAcosA
sin
2
A+cos
2
A
1
=sinAcosA where sin
2
A+cos
2
A=1
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