Question

B. SOLVE THE FOLLOWING EQUATIONS :
1) 3a + 4 = 10
2) 6y + 15 = 12
​

Answer 1

Answer:

Simplifying

3a + 4 = 10

Reorder the terms:

4 + 3a = 10

Solving

4 + 3a = 10

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + 3a = 10 + -4

Combine like terms: 4 + -4 = 0

0 + 3a = 10 + -4

3a = 10 + -4

Combine like terms: 10 + -4 = 6

3a = 6

Divide each side by '3'.

a = 2

Simplifying

a = 2

Explanation:

Subtract

1

5

15

15

from both sides of the equation

6

+

1

5

=

1

2

6y+15=12

6y+15=12

6

+

1

5

−

1

5

=

1

2

−

1

5

Answer 2

$\LARGE{\underline{\underline{\sf{Answer:-}}}}$

1) a = 32

2) y = 0.5

______________

Explanation:

1) 3a + 4 = 10

» 3a + 4 = 100

» 3a = 100 – 4

» a = $\frac{96}{4}$

» a = 32

____________

2) 6y + 15 = 12

» 6y + 15 = 12

» 6y = 12 – 15

» y = $\frac{3}{6}$

» y = 0.5