(B) Solve the following questions.
i. In the adjoining figure, BC perpendicular AB, AD perpendicular AB,
BC = 4, AD = 8, then find
A(triangle ABC)
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A(triangle ADB)
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area of triangle=(base×height)/2
area of triangle ABC = (BC×AB)/2=(4×AB)/2=2AB
area of triangle ADB = (AD×AB)/2=(8×AB)/2=4AB
=2×2AB
=2× area of triangle ABC
area of triangle ADB = 2× area of triangle ABC
Area of triangle ABC= half of Area of triangle ADB
= (Area of triangle ADB)/2
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