Question

b) Solve the system of simultaneous linear equations by cross
multiplication method:
3x + 2y = 4
3x + 5y = 9
​

Answer 1

Answer:

x=2/9 , y= 0

Step-by-step explanation:

$x \div b1c2 - b2c1 = y \div c1a2 - c2a1 = 1 \div a1b2 - a2b1$

3x+2y-4=0

3x+5y-9=0

x/(2)(-9) - (5)(-4) = y/(-4)(3) - (-4)(3) = 1/(3)(5) - (3)(2)

x/(-18)-(-20) = y/(-12)-(-12) = 1/(15)-(6)

x/-18+20 = y/-12+12 = 1/15-6

x/2 = y/0 = 1/9

y/0 = 1/9

9y = 0

y= 0

x/2 = 1/9

9x=2

x=2/9