Question

b square – ab(1 – a)-a cube​

Answer 1

$\huge\bold\red{hey}$

Answer: (by grouping method)

b² - ab (1 - a) - a³

=> b² - ab + a²b - a³

=> b(b - a) + a²(b - a)

=> (b - a)(b + a²)

hope it's gonna help you ☺

Answer 2

Answer:

b² - ab (1 - a) - a³

=> b² - ab + a²b - a³

=> b(b - a) + a²(b - a)

=> (b - a)(b + a²)