Physics, asked by ghulamm2390388, 8 months ago

b
T
A boy throws a ball upward from the top of a cliff wit
speed of 14.7 m/s. On the way down it just misses
thrower and fall the ground 49 metres below. Find (1)
long the ball rises? (11) How high it goes? (111) How long
in air and (iv) with what velocity it strikes the ground.​

Answers

Answered by amritaprasad8b
5

Answer:

Explanation:The ball rises for v/g seconds; which equals 14.7/9.8=1.5 seconds . After this ... A boy throws a ball upward from the top of the cliff with a speed of 14.7 m/s. On the way down, it just misses the thrower and falls to the ground 49m below. ... A ball is thrown with a velocity of 6.0 m/s is thrown straight off a 30 meter high building.

hope it helps

Answered by valjichohan382
0

Answer:

s=vit+1/2gt^2

Explanation:

14.7t+1/2'10(t)^2

Similar questions