Math, asked by hggupta2994, 1 year ago

B takes 5 days more than A to complete a certain work. A started the work and after 6 days B joined him. But 17 days before the completion of the work A left it and so A got only Rs.524 out of the total of Rs.1310 for entire work
In how many days can B alone can complete the entire work.

Answers

Answered by amitnrw
1

Answer:

45 Days

Step-by-step explanation:

Let say A complete  work  in  A  days

Then B completes the work in A + 5 Days

A got only Rs.524 out of the total of Rs.1310

=> A work  = 524/1310  = 2/5

& B Work = (1310 - 524)/1310 = 3/5

Let say A & B Worked for X days together

A worked  for   X + 6 Days

B Worked for   X + 17 Days

A's Work  = (X + 6)/A    &  B's Work  = (X + 17)/(A + 5)

(X + 6)/A =  2/5

=> 5X + 30 = 2A

=> 5X = 2A - 30

(X + 17)/(A + 5) = 3/5

=> 5X +85 = 3A + 15

=> 5X = 3A - 70

Equating 5X

2A - 30 = 3A - 70

=> A = 40

B completes the work in A + 5 Days = 40 + 5 = 45 Days

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