Question

*बिंदुओं A(6,8) और B(3,4) के बीच की दूरी ____ है।*

1️⃣ 5 इकाई
2️⃣ 12 इकाई
3️⃣ 10 इकाई
4️⃣ 25 इकाई​

Answer 1

$\underline{\textsf{Given:}}$

$\textsf{A(6,8) and B(3,4)}$

$\underline{\textsf{To find:}}$

$\textsf{The distance between A and B}$

$\underline{\textsf{Solution:}}$

$\textsf{Concept:}$

$\textsf{The distance between the points}\;\mathsf{(x_1,y_1)\;\textsf{and}\;\mathsf{(x_2,y_2)}}$

$\mathsf{d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\textsf{The distance between A(6,8) and B(3,4)}$

$\mathsf{=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\mathsf{=\sqrt{(6-3)^2+(8-4)^2}}$

$\mathsf{=\sqrt{3^2+4^2}}$

$\mathsf{=\sqrt{9+16}}$

$\mathsf{=\sqrt{25}}$

$\mathsf{=5}\;\textsf{units}$

$\underline{\textsf{Answer:}}$

$\textsf{The distance between A(6,8) and B(3,4) is 5 units}$

$\textsf{Option(1) is correct}$

Find more:

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Find all possible values of x for which the distance between the points A ( X , - 1) and B ( 5 , 3) is 5 units

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Answer 2

Step-by-step explanation:

HELLO DEAR,

बिनदू A(6,8) और B(3,4)

AB= √{(6-3)^2 + (8-4)^2}

=√{(3)^2 + (4)^2}

= √(9+16)

=√25

AB =5.

a) 5 इकाईI

I HOPE IT HELP YOU DEAR,

THANKS.