Question

(b) The 2500 em of H, is subjected to 2, times increase
in pressure (temp. remaining constant). What volume
will H, now occupy ?​

Answer 1

Answer:

If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase. However, if you were to maintain a constant volume while decreasing pressure, the temperature would also have to decrease.

Answer 2

Answer: 2500/3

Explanation:

V1=2500, P1=760mm

V2=?, P2= 2 times increase in P1

P2 = 760 + ( 2 * 760)

=760 + (1520)

P2 =2280 mm

P1V1 = P2V2

V2 = P1V1 / P2

V2 = (2500 * 760) / 2280

= (2500) / 3

V2 = 2500/3