(b) The amount of metal in a hollow cylinder
with height 14 decimetre and external
diameter 5 decimetre is 42.24 cubic
decimetre. Find the thickness of the
cylinder
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given,
height= 14 decimeter= 1.4m
diameter= 5 decimeter= 0.5m
(∴radius= 0.25 as r=d/2)
volume= 42.24cm3
solution,
let external thickness be x
so, total radius is (0.25+x)
(as total radius-= radius+thickness)
now,
volume of cylinder= π r2 h= π (0.25+x)2 (1.4)
42.24= π (0.25+x)2 (1.4)
9.6= 0.0625+x2+0.5x
9.5375-x2-0.5x=0
(let us assume 9.5375 as 9.5 for convenience of our calculation)
so, x2+0.5x-9.5= 0
bro now u can solve it by mid term split, the positive value would be your answer as radius can't come in negative :))
thank you!! :D
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