Question

b. The area of the base of a circular cylinder is 44sq.cm and its volume is 660cu.cm. Then its height​

Answer 1

$\sf{\huge{\underline{Given :-}}}$

• The area of the base of a circular cylinder is 44sq.cm and its volume is 660cu.cm.

$\sf{\huge{\underline{To\:Find :-}}}$

• The height of the cylinder.

$\sf{\huge{\underline{Answer :-}}}$

We have,

The area of the base of a circular cylinder is 44sq.cm

We know, The area of the base of a circular cylinder = π r²

➝ π r² = 44

➝ r² = 44 × 7 /22

➝ r² = 2 × 7

➝ r² = 14 -------(1)

The volume of cylinder is 660 cm³.

We know, The volume of cylinder is πr²h

So, πr²h = 660

From (1) equation,

π × 14 × h = 660

➝ h = $\dfrac{660}{\pi \times 14}$

➝ h = $\dfrac{660 \times 7}{14 \times 22}$

➝ h = $\cancel{\dfrac{4620}{308}}$

➝ h = 15 cm

The height of the cylinder is 15 cm.

Answer 2

Given:-

• Area of the base of a circular cylinder is 44 cm².
• Its Volume = 660 cm³

To Find:-

• Its Height

Formula used:-

• Area of Circle = πr²
• Volume of Cylinder = πr²h

Solution:-

Firstly,

Area of base = πr²

44 = $\dfrac{22}{7}r²$

r² = 7 × 2

r² = 14 ____ {1}

Now,

Volume of Cylinder = πr²h

660 = $\dfrac{22}{7}×14×h$ {from 1}

660 = $22×2×h$

660 = $44×h$

h = $\dfrac{660}{44}$

h = $15 \: cm$

Hence, the height of the given cylinder is 15 cm.

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