Question

b) The base of a right triangle is 4 cm longer than its height. If
the area of the triangle is 48 sq.cm, then find its base and
height?​

Answer 1

Answer:

8

Step-by-step explanation:

ANSWER

Base of a triangle is 4 cm longer than its altitude.

Area of triangle =48 cm

2

Let base of triangle =b

Altitude =b−4

Area =

2

1

×b×h=48

2

1

×b×(b−4)=48

b

2

−4b−96=0

(b−12)(b+8)=0

But, base cannot be negative

So, base =12 cm

Altitude=12−4=8 cm.

Answered By Satyam kaushik

Answer 2

Hey mate,

Base of a triangle is 4 cm longer than its altitude.

Area of triangle =48 cm 2

Let base of triangle =b

Altitude =b−4

Area = 21×b×h=4821 ×b×(b−4)=48b2 −4b−96=0

(b−12)(b+8)=0

But, base cannot be negative

So, base =12 cm

Altitude=12−4=8 cm.

Hope it helps....

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