(b) The circumference of a circular field is
440 m. Find the cost of levelling the field
at the rate of 5 per sq. m.
Take pi=
22/7
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5
Answer:
15400 m^2
Step-by-step explanation:
2 22/7 r = 440
22/7 r = 440/2
r = (440)7/(22)2
r= 440 * 7/44
r = 10*7
r = 70m
Area = 22r^2/7
= 22(70)^2/7
= 22(4900)/7
= 22(700)
= 15400 m^2
1m^2 = ₹5
15400 m^2 = ₹5 * 15400
= ₹77,000
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