Question

B. The common solution of the simultaneous linear
equations x - 3y + 6 = 0 and 4x + y - 15 = 0 is​

Answer 1

Step-by-step explanation:

the above attachment has the answer

Answer 2

Answer:

x = 3, y = 3

Step-by-step explanation:

x - 3y + 6 = 0 .............(1)

4x + y - 15 = 0 ............(2)

Now,

$Multiplying \ equation \ (2) \ by \ 3\\Equation(2) = 12x + 3y - 45 = 0\\Adding \ (1) \ and \ (2)\\(x + 12x) + (-3y + 3y) + (6 - 45) = (0+0)\\13x -39 =0\\13x = 39\\x = \frac{39}{13} = 3\\\\x = 3\\In \ equation \ (1)\\x - 3y + 6 = 0\\3 - 3y + 6 = 0 \ putting \ value \ of \ x \ from \ above\\-3y + 9 = 0\\ -3y = -9\\y = \frac{-9}{-3} = 3\\y = 3$

Therefore

x = 3, y = 3