(b) The density of aluminium is 2.70g/cm². The thickness of a rectangular sheet of
aluminium foil varies, but is much less than 1 mm.
A student wishes to find the average thickness. She obtains the following measurements.
mass of sheet = 60.79
length of sheet = 50.0 cm
width of sheet = 30.0 cm
Calculate the student's values for
(1) the volume of the sheet,
volume =
[2]
(II) the average thickness of the sheet.
Answers
Answer:
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Answer:
First, calculate the volume of the aluminium foil. This can be obtained by using the formula: Volume = Mass/Density. To use this formula, the mass must first be expressed in grams since the density is in g/cm^3.
Mass of foil = 440. mg*(1 g/1000 mg) =0.440 g
Volume = 0.440 g ÷ 2.70 g/cm^3 = 0.16296 cm^3
Now, volume of the piece of aluminium foil = surface area * thickness. This is equivalent to length * width * height. Here, the height is the thickness.
Thus:
10.00*10.00*h = 0.16296
100h =0.16296
h = 0.16296/100
h = 0.0016296
h = 0.00163 cm (to 3 significant figures)
The thickness of the piece of foil is 0.00163 cm or 1.63 x 10^-3 cm.