Question

(b) The diagonal of a rectangle is 25 cm and its length is 20 cm. Find the breadth and perimeter of
the rectangle.

Answer 1

Answer: breadth=15cm & perimeter=300

Step-by-step explanation:let ABCD be the rect.

So, ABD=right angle triangle

therefore

using phythgoras theorum,

(HERE,2 IMPLIES SQUARE)

h2=p2+b2

25*25=AB2+20*20

625-400=AB2

225=AB2

15=AB

So,peri.=l*b=20*15

                     =300

Answer 2

Answer:

Let us use Pythagoras theorem here,

let ABCD is a quadrilateral

where, AC = 25 cm

AB =20 cm

BC =?

Taking triangle ABC

AC²= AB² + BC²

BC²= AC²-AB²

BC²=(25) ²-(20) ²

BC²=625-400

BC=√225

BC=√(15) ²

BC= 15 cm

so, breadth is 15 cm .

NOW ,

perimeter = 2(l+b)

= 2( 20 +15) cm

= 2(35)Cm

= 70Cm

Therefore, breadth is 15 Cm and perimeter of the rectangle is 70Cm