Math, asked by deepaksc71, 4 months ago

b. The digit on the second die is greater than the digit

on first die.​

Answers

Answered by khananad36
0

Answer:

Hence, the probability that the sum of the digits on the upper faces is at least 10 is 16. Hence, the probability that the sum of the digits on the upper faces is 33 is 0. Hence, the probability that digit on the first die is greater than the digit on second die is 512

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