Question

B) the equation for the action of heat on calcium nitrate is: 2ca(no3)2 2cao + 4 no2 + o2 (i) how many moles of no2 are produced when 1 mole of ca(no3)2 decomposes? (ii) what volume of o2 at s.T.P. Will be produced on heating 65.6 g of ca (no3)2? (iii) find out the mass of cao formed when 65.6 g of ca(no3)2 is heated. (iv) find out the mass of ca(no3)2, required to produce 5 moles of gaseous products. (v) find out the mass of ca(no3)2 required to produce 44. 8 l of no2 at s.T.P. (relative molecular mass of ca(no3)2 = 164 and of cao = 56)

Answer 1

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