Question

(b) The half-life period of a first order
reaction is 100 sec. Calculate the time
required for 80% completion. ​

Answer 1

Answer:

b) answers

Explanation:

k= (2.303/t)log(initial conc./final conc.) After consuming 80% of the reactant, the final concentration will be 20% of the initial concentration. t = 231.96 secs. Therefore it takes 231.96 secs. to consume 80% of the reactant.