Math, asked by aryanson6669, 3 months ago

(b) The midpoint of theline segment joining the points E(8, 11) and B(11, 15) is

(i) (6, 10) (ii) 11 8

,

5 5

      (iii) 15 17,

4

      (iv) 19 ,13

2

   ​

Answers

Answered by RvChaudharY50
11

Given :- The midpoint of theline segment joining the points E(8, 11) and B(11, 15) is ?

\bf\red\bigstar\underline\textbf{\blue{Concept}\:\pink{used}}\red\bigstar :-

✰) The midpoint of the line segment joining the points P (x₁,y₁) and Q(x₂,y₂) is : ---

\purple{\tt\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}}

Solution :-

we have ,

  • x₁ = 8
  • y₁ = 11
  • x₂ = 11
  • y₂ = 15

Let us assume that, Mid - Points are (x,y) .

then,

→ x = (8 + 11)/2 = 19/2 = 9.5

→ y = (11 + 15)/2 = 26/2 = 13 .

Hence, Mid - Points of line segment are (9.5,13).

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Answered by pulakmath007
35

SOLUTION

TO CHOOSE THE CORRECT OPTION

The midpoint of the line segment joining the points E(8, 11) and B(11, 15) is

(i) (6, 10)

(ii) (11/5, 8/5)

(iii) (15/4 17/4)

(iv) (19/2 ,13)

CONCEPT TO BE IMPLEMENTED

 \sf{If  \: two  \: points \:  \: ( x_1,y_1) \: and \: (x_2,y_2)  \: are \:  given }

Then the midpoint of the line joining the points is

 =  \displaystyle \sf{  \bigg( \:  \frac{x_1 + x_2 \: }{2} ,  \frac{y_1 + y_2 \: }{2} \bigg)\:  \: }

EVALUATION

Here the two given points are E(8, 11) and B(11, 15)

So the midpoint of the line segment joining the points E(8, 11) and B(11, 15) is

 =  \displaystyle \sf{  \bigg( \:  \frac{8+ 11 \: }{2} ,  \frac{11 + 15\: }{2} \bigg)\:  \: }

 =  \displaystyle \sf{  \bigg( \:  \frac{ 19 \: }{2} ,  \frac{26\: }{2} \bigg)\:  \: }

 =  \displaystyle \sf{  \bigg( \:  \frac{ 19 \: }{2} ,  13 \bigg)\:  \: }

FINAL ANSWER

The midpoint of the line segment joining the points E(8, 11) and B(11, 15) is

  \displaystyle \sf{ (iv) \:  \:  \:  \:  \:  \:  \bigg( \:  \frac{ 19 \: }{2} ,  13 \bigg)\:  \: }

━━━━━━━━━━━━━━━━

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