Question

(b) The near point of a hypermetropic eye is 1 m. Find the power of the
lens required to correct this defect. Assume that near point of the
normal eye is 25 cm​

Answer 1

Explanation:

The convex lens required to correct hypermetropic

U=-25

V= - 1m= - 100cm

Using lens formula: 1/f=1/v-1/u

1/f = - 1/100-1/-25

=-1/100+1/25

= - 1+4/100

= - 3/100cm^-1

Power:: p=1/f

= 3/100*100D

P= 3D....

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