Question

b) The perimeter of a triangle is 480 m and it's sides are in the ratio 1:2:3. Find the area of
triangle.
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Answer 1

$\Huge\mathfrak{answer \: !}$

Step-by-step explanation:

The perimeter of a triangle is 480 metres and its sides are in the ratio of 1:2 : 3 find the area of a triangle. 3072000 m. sqr.

please take reference from the attachment

Answer 2

Step-by-step explanation:

$\blue{ \bf{ \underline{Question : - }}}$

The perimeter of a triangle is 480 m and it's sides are in the ratio 1:2:3. Find the area of

triangle.

$\boxed{ \huge{ \bold{Given}}}$

• Perimeter of a Triangle = 480 m

• Ratio of the Sides = 1:2:3

$\boxed{ \huge{ \bold{ to \: find}}}$

• Area of the Triangle

$\star{ \pink{ \underline{ \underline{Ｓｏｌｕｔｉｏｎ : - }}}}$

$\huge{ \bold{ \underline{Let}}}$

• 1st side = x

• 2nd side = 2x

• 3rd side = 3x

$\underline{ \underline{Now}}$

$\: \: \: \: \: \: \: \: \: \: \: {\sf{premier \: of \: the \: Triangle = x + 2x + 3x}}$

$\: \: \: \: \: \: \: \: \: \: \: { \implies {\sf{480 = 6x}}}$

$\: \: \: \: \: \: \: \: \: \: \: { \implies {\sf{ \cancel\frac{480}{6} = x}}}$

$\: \: \: \: \: \: \: \: \: \: \: { \implies {\sf{80 = x}}}$

Now,

• x = 80

• 2x = 2× 80 = 160

• 3x = 3× 80 = 240

$\: \: \: \: \: \: \: \: \: \: \: { \sf{S = \frac{80 + 160 + 240}{2}}}$

$\: \: \: \: \: \: \: \: \: \: \:{ \implies { \sf{S = \cancel\frac{480}{2}}} }$

$\: \: \: \: \: \: \: \: \: \: \: { \sf{ \pink{S = 240}}}$

$\boxed{ \red{ \sf{Formula \: Of \: triangle = \sqrt{s} (s - a)(s - b)(s - c)}}}$

$\: \: \: \: \: \: \: \: \: \: \: { \sf{ = \sqrt{24} (240 - 80)(240 - 60)(240 - 240)}}$

$\: \: \: \: \: \: \: \: \: \: \: { \sf{ = 240 \times 160 \times 80 \times 0}}$

$\: \: \: \: \: \: \: \: \: \: \: { \sf{ = {\pink{0 \: {m}^{2} }}}}$

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