Question

b. The population of a town in Russia increases 10% every year. If its present population is 3,25,000 fin
i.its population two years ago
il its population after two years.
Saumbh invests Rs.48.000 for 7 years at 10% per annum compound Interest. Calculate:​

Answer 1

Answer:

Let the population before two years ago be x

Given the population increases by 10%

So increase in population after one year is  

100

10

​

×x=0.1x

So population after one year is x+0.1x=1.1x

Increase in population after another one year is  

100

10

​

×1.1x=0.11x

So population at present is 1.1x+0.11x=1.21x

But given population at present is 3,02,500

⟹1.21x=302500

⟹x=  

1.21

302500

​

=2,50,000

Population of city two years ago is 2,50,000