B) The sides EF, FD and DE of a triangle DEF are produced in order
forming three exterior angles ZDFP, ZEDQ, ZFER respectively, then
prove that ZDFP+ZEDQ+ZFER=360°.
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solution is in the photo
hope it helps
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Step-by-step explanation:
In ∆DEF
angel D+angel E+angel F=180
angel EDQ =angel E+angel F
angel FER =angel D+ angel E/ angel EDQ+ angel FER +angel DEF = 2 angel p+2angle E + 2angle E
= 2 [angel D+angel E+ angel F]
= 2[180]
=360⁰
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