Question

b) The sum of factors of frinomial 5y2 - 2y - 3
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Answer 1

Answer:

Factoring 5y2-2y-3

The first term is, 5y2 its coefficient is 5 .

The middle term is, -2y its coefficient is -2 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 5 • -3 = -15

Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is -2 .

-15 + 1 = -14

-5 + 3 = -2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 3

5y2 - 5y + 3y - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

5y • (y-1)

Add up the last 2 terms, pulling out common factors :

3 • (y-1)

Step-5 : Add up the four terms of step 4 :

(5y+3) • (y-1)

Which is the desired factorization

Final result :

(y - 1) • (5y + 3)