Question

b. The sum of three consecutive multiples of 4 is
108. Find those numbers.​

Answer 1

Answer:

Let us suppose, the numbers are x, x +3 and x+6

Sum of them is:

x + (x +3) + (x+6) = 108

=> 3x + 9 = 108

=> 3x = 99

=> x = 33, which is divisible by 3

So the number are 33 (x), 36 (x+3) and 39 (x+6).

Step-by-step explanation:

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