Question

b. The sum of three consecutive multiples of 4 is
108. Find those numbers.​

Answer 1

Answer:

32,36,40

Step-by-step explanation:

Let the multiples of 4 be x, x+4, x+8

x + x + 4 + x + 8 = 108

3x + 12 = 108

3x = 108 - 12

3x = 96

x = 96/3

x = 32

x + 4 = 36

x + 8 = 40

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Answer 2

Let the three consecutive multiples of 4 be x, x+4, x+8 say.

As per problem,

• x+x+4+x+8 = 108
• 3x + 12 = 108
• 3x = 108-12
• x = 96/3
• x = 32

Therefore, the three consecutive multiples :

• x = 32
• x+4 = 32+4 = 36
• x +8 = 32+8 = 40

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