Question

B) there is an object infront of convex mirror at a distance of 5cm. if its focal
length is 10cm then
a) What is the image distane?
b) What is itd magnification ?​

Answer 1

Answer:

u = -5cm, f = 10cm

We know that

1/v + 1/u = 1/f

⇒ 1/v + 1/-5 = 1/10

⇒ 1/v = 1/10 + 1/5 = 3/10

∴ v = (10/3)cm = 3.33 cm

The position of the image is 3.33 cm behind the convex mirror.

Magnification, m = -v/u = -3.33/-5 = 0.66

The image is virtual and erect.

THANK U AND MARK AS BRAINNLIEST

Explanation:

Answer 2

Answer:

a) image will form at backside the mirror at 10 cm

b) this required height of object and image

magnification = height of object /that of image