Question

B to the power 2 -
9(b-1) to the power 2

Answer 1

$b^{2} - 9(b-1)^{2} \\= b^{2} - [3(b-1)]^{2} \\= b^{2} - (3b-3)^{2} \\= [b+(3b-3)][b-(3b-3)]$

$\boxed { \pink { x^{2} - y^{2} = (x+y)(x-y) }}$

$= ( b + 3b - 3 )( b - 3b + 3 ) \\= (4b - 3)( 3 - 2b )$

Therefore.,

$\red {b^{2} - 9(b-1)^{2}} \green {= (4b - 3)( 3 - 2b ) }$

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