B twice asbefficient as a and a can do a peace of work in 21 days .A started the work and after a few days b joined him.They com0leted the work in 15 days from starting .For how many days did they work
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Answer:
9 days
Step-by-step explanation:
A can do a piece of work in 40 days. Assume that total work is 40 units such that
work done by A in 1 day = 1 unit
Since B is twice as efficient as A,
work done by B in 1 day = 2 unit
Work done by A and B in 1 day = 1 + 2 = 3 units
Suppose A alone worked in the initial
x
days and then A and B together worked for
(
22
−
x
)
days and work got completed.
x
×
1
+
(
22
−
x
)
×
3
=
40
x
+
66
−
3
x
=
40
2
x
=
26
x
=
13
Required number of days in which they worked together
=
(
22
−
x
)
=
9
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