b. two cubes each of edge 5 cm are joined face to face. The surface area of the cuboid. Thus
formed is:
i. 200cm2
ii. 250cm2
iii. 360cm2
iv. 400cm2
Answers
Answer:
The surface area of cuboid is 250 cm².
Explanation :
If two cubes, each of edge 5 cm are joined, then the length (l) of the resulting cuboid will become (2×5)cm = 10cm.
The breadth (b) and height (h) will remain 5 cm.
So, the dimensions of the resulting cuboid will be 10 cm ×5 cm ×5 cm.
We know, surface area (S.A.)of a cuboid is given as:
SA = 2(lb + bh + lh) where l is the length, b is the breadth and h is the height.
Putting their respective values, we get Surface area as:
2(10×5+ 5×5+ 10×5) cm²
= 2 (50 + 25 + 50) cm²
= 2 (125) cm²
= 250 cm²
So, surface area is 250 cm².
Answer:
ii)Side of each cube = 5 cm
When they are joined they become cuboid.
Length of cuboid = 10 cm
Breadth of cuboid = 5 cm
Height of cuboid = 5 cm
Lateral/ Curved Surface Area of cuboid
= 2(l+b) h
= 2×(10+5)×5
= 2× 15×5
= 150 cm^2
Total Surface Area of cuboid
= 2(lb+lh+bh)
= 2(10×5+10×5+5×5)
= 2(50+50+25)
=2×125
= 250 cm^2.