(b) Two electric bulbs are rated 60 W - 220 V and 100 V
- 220 V respectively. Both are connected in series to an electri
supply of 220 volts. Calculate the current flowing in the electri
bulbs.
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Answer:
The resistance of the bulb is given by R=V2/P. So the resistance of 60 W bulb is more than the resistance of 100 W bulb. When they are connected in series the current through both bulbs is same. Hence 60 W bulb will be more brighter because P = I2R.
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I don't know but I tried to solve
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