Question

b)
Two point charges of +1 uC and + 4 uC are kept 30 cm apart. How
far from the + 1 uC charge on the line joining the two charges, will
the net electric field be zero?​

Answer 1

The net electric field will be zero at distance 10 cm from +1μC.

Explanation:

Given that,

First point charge = +1 μC

Second point charge = +4 μC

Distance = 30 cm

Let us consider the net electric field zero at x distance from first charge.

We need to calculate the electric field

Using formula of electric field

$E_{x}=E_{30-x}$

$\dfrac{kq}{r^2}=\dfrac{kq}{r'^2}$

Put the value into the formula

$\dfrac{1\times10^{-6}}{x^2}=\dfrac{4\times10^{-6}}{(30-x)^2}$

$\dfrac{(30-x)^2}{x^2}=\dfrac{4\times10^{-6}}{1\times10^{-6}}$

$\dfrac{30-x}{x}=\sqrt{\dfrac{4}{1}}$

$30-x=2x$

$x= 10\ cm$

Hence, The net electric field will be zero at distance 10 cm from +1μC.

Learn more :

Topic : electric field

https://brainly.in/question/12798714

Answer 2

Answer:

lol

Explanation:

idk the answer