Question

b) Two point charges Q1 - 250 uC and Q2 = 300 uC are located at (5, 0, 0)m and
(0,0,-5)m respectively. Find the force on q1​

Answer 1

Answer:

3.375*10^16

Explanation:

F=Cqq/d^2

here,

d=√(5^2+(-5)^2)

=5√2

F=9*10^9*250*300/(5√2)^2

=3.375*10^16