Question

b) Two resistors, 2 ohm and 3 ohm,
are connected in series across a
battery of 10 V. How much energy
will be used by the 3 ohm resistor in
5 seconds? (2)

pls help​

Answer 1

Answer:

ANSWER

(a) Req =

3+2

3×2

=

5

6

=1.2Ω

(b) V=IR⇒I=

R

V

⇒I=

1.2

12

=10A

(c) 3(10−i)=2i (∵ Potential drop in parallel combination are same)

⇒30−3i=2i⇒30=5i⇒i=6A

Current in 2Ω resistor is =i=6A

Current in 3Ω resistor is =10−i=4A

solution

Explanation:

Hope this helps