Physics, asked by viddhyanidhi5219, 9 months ago

b. Two tungsten bulbs of wattage 200 W and 40 W power work on 240 V potential difference. If they are connected in parallel, how much current will flow in the main conductor?

Answers

Answered by jaydas2000
0

Answer:

The 200 W bulb will draw 200/240 = 5/6 Ampere

and the 40 W bulb will draw 40/240 = 1/6 Ampere from the source.

Therefore the current in the main conductor,

I = I1 + I2 = 5/6 + 1/6 = 1 Ampere

Explanation:

As the bulbs are connected in parallel combination, the Voltage remains same in both, i.e. V1 = V2 = V = 240 Volt.

Now, we know that electrical power, P = Voltage (V) × Current (I)

From the above equation we can find the current consumption of both the bulbs.

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