Question

(b)
Using ideal gas equation, evaluate R and express
its units​

Answer 1

Hey dear,

● Answer -

R = 8.314 J/molK

● Ideal gas constant -

aka universal gas constant

Denoted by R

● Calculation -

# Given -

For 1 mole of ideal gas at STP,

n = 1

T = 273 K

P = 1.013×10^5 Pa

V = 0.02241 m^3

# Solution-

According to ideal gas equation -

PV = nRT

R = PV / nT

R = 1.013×10^5 × 0.02241 / 1 × 273

R = 8.314 J/molK

Hope this helps you...

Answer 2

Answer:

Ideal Gas Equation is:  

PV = nRT  

where:

1. R is the ideal gas constant [with the value= 0.08205] [units= liter-atmospheres-per-mole-Kelvin (L atm K-1 mol-1)]

2. P is pressure of the gas [units- atmospheres (atm)]  

3. V is volume of the gas [units- liters (L)].

4. n is the amount of gas [units- moles].  

5. T is the temperature of the gas [units= Kelvin (K)]

Evaluation

In STP condition:

The volume of 1 mol of any gas at Standard temperature 273.15 K and pressure 1 atm is measured to be 22.414 L.

We can substitute -

P= 101.325 kPa  

V=  22.414 L

T=  273.15 K  

R=PV/nT

R=101.325×22.414/1.000×273.15

R=8.314 kPa⋅L/K⋅mol