Physics, asked by nandmohansingh00, 4 months ago

b) Using Moseley’s law, obtain the frequency of an X-ray line when L to K transition
takes place in silver atom. It is given that б = 3.

Answers

Answered by s1676ixautkrishtmaha
0

Answer:

The frequency

ν

of a characteristic X-ray of an element is related to its atomic number

Z

by

ν

=

a

(

Z

b

)

,

where

a

and

b

are constants called proportionality and screening (or shielding) constants. For

K

series, the value of

a

is

3

R

c

/

4

and that of

b

is 1. Here

R

is Rydberg's constant and

c

is speed of light (as in Bohr's model). For

L

series, the value of

a

is

5

R

c

/

36

and

b

is 7.4. The relation and values of

a

and

b

are experimentally determined by Henry Moseley.

Explanation:

Solved Problems on Moseley's Law

Problem from IIT JEE 2003

Characteristic X-rays of frequency

4.2

×

10

18

Hz are produced when transitions from

L

-shell to

K

-shell take place in a certain target material. Use Moseley's law to determine the atomic number of the target material. (Rydberg's constant

=

1.1

×

10

7

m

1

.)

Solution:

The characteristic X-ray is emitted when an electron in

L

shell makes a transition to the vacant state in

K

shell. In Moseley's equation,

ν

=

a

(

Z

b

)

,

the parameter

b

1

for this transition because electron from

L

shell finds nuclear charge

Z

e

shielded by remaining one electron in

K

shell i.e., effective nuclear charge is

(

Z

1

)

e

. Thus, by substituting values,

1

λ

=

ν

c

=

4.2

×

10

18

3

×

10

8

=

R

(

Z

1

)

2

[

1

n

2

1

1

n

2

2

]

=

1.1

×

10

7

(

Z

1

)

2

[

1

1

2

1

2

2

]

,

which gives,

Z

=

42

. Moseley's law played key role in arrangement of elements in the periodic table and to find many new (missing) elements.

Problem from IIT JEE 2014

If

λ

C

u

is the wavelength of

K

α

X-ray line of copper (atomic number 29) and

λ

M

o

is the wavelength of the

K

α

X-ray line of molybdenum (atomic number 42), the the ratio

λ

C

u

/

λ

M

o

is close to

1.99

2.14

0.50

0.48

Solution:

The wavelength of

K

α

X-ray line is related to atomic number

Z

by Moseley's Formula

1

λ

=

R

(

Z

1

)

2

[

1

1

2

1

2

2

]

=

3

4

R

(

Z

1

)

2

.

Substitute the value of

Z

to get

λ

C

u

λ

M

o

=

(

Z

M

o

1

)

2

(

Z

C

u

1

)

2

=

(

41

)

2

(

28

)

2

=

2.14.

The elements with higher atomic number (molybdenum in this example) gives high energy X-rays (short wavelengths).

Problem from IIT JEE 2008

Which of the following statements is wrong in the context of X-rays generated from a X-ray tube?

Wavelength of characteristic X-rays decreases when the atomic number of the target increases.

Cut-off wavelength of the continuous X-rays depends on the atomic number of the target.

Intensity of the characteristic X-rays depends on the electrical power given to the X-ray tube.

Cut-off wavelength of the continuous X-rays depends on the energy of the electrons in the X-ray tube.

Solution:

The frequency

ν

of characteristic X-rays is related to atomic number

Z

by Moseley's law,

ν

=

a

(

Z

b

)

,

which gives

λ

=

c

ν

=

c

a

2

(

Z

b

)

2

.

Thus, the wavelength of emitted X-rays decreases with increase in

Z

. The cut-off wavelength of continuous X-rays corresponds to maximum energy of electron in X-ray tube. It is given by

h

c

/

λ

=

e

V

,

where

V

is the accelerating potential. The intensity of X-rays depends on the number of electrons striking the target per second, which, in turn, depends on the electrical power given to the X-ray tube as energy of each electron is

e

V

.

Questions on Moseley's Law

Question: If 178.5 pm is the wavelength of X-ray line of copper (atomic number 29) and 71 pm is the wavelength of the X-ray line of molybdenum (atomic number 42) then the value of a and b in Moseley's equation are

A.

a

=

7

×

10

7

H

z

1

/

2

, b=1.0

B.

a

=

5

×

10

7

H

z

1

/

2

, b=7.4

C.

a

=

5

×

10

7

H

z

1

/

2

, b=1.4

D.

a

=

7

×

10

7

H

z

1

/

2

, b=7.4

Question: Moseley's Law for characteristic X-rays is

ν

=

a

(

Z

b

)

. In this formula

A. both a and b are independent on the material.

B. a is independent but b depends on the material.

C. b is independent but a depends on the material.

D. both a and b depend on the material.

Related Topic

Characteristic and Continuous X-rays | Problems | IIT JEE

References and External Links

Concepts of Physics Part 2 by HC Verma (Link to Amazon)

IIT JEE Physics by Jitender Singh and Shraddhesh Chaturvedi

X-ray Fluorescence and Moseley’s Law (pdf article on X-rays, Moseley's

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