Question

b. What is the acceleration produced by a force of 12 kg-m/s’exerted on an object of mass 400 gm?
OR

Answer 1

Answer:

Explanation:

Given :

• Force (F) exerted on an object is 12 kg.m/s.
• Mass (m) of an object is 400 gm.

To Find :

• The acceleration produced by a force.

Formula to be used :

• Newtons 2nd law of motion, ie,, F = ma.

Solution :

★ Converting units,

Mass = 400 gm

⇒ m = 400/1000

⇒ m = 0.4 kg

★Acceleration produced by a force,

F = ma

⇒ 12 = 0.4 × a

⇒ a = 12/0.4

⇒ a = 30 m/s²

Hence, The acceleration produced by a force is 30 m/s².

Answer 2

${\bold{\sf{\underline{Understanding \: the \: question}}}}$

✵ This question says that we have to find the accreditation produced by the Force and it's exerted on 12 kg-m/s on an object of mass 400 grams.

${\bold{\sf{\underline{Given \: that}}}}$

❈ Mass = 400 grams

❈ Exerted force = 12 kg-m/s

${\bold{\sf{\underline{To \: find}}}}$

❈ Accreditation produced by force.

${\bold{\sf{\underline{Solution}}}}$

❈ Acceleration produced by force = 30 m/s²

${\bold{\sf{\underline{Using \: concept}}}}$

❈ Newton's 2nd law of equation formula

${\bold{\sf{\underline{Using \: formula}}}}$

❈ Newton's 2nd law of equation → F = ma

${\bold{\sf{\underline{We \: also \: denote \: these \: as}}}}$

✵ Acceleration as a

✵ Force as F

✵ Mass as m

${\bold{\sf{\underline{Some \: procedure}}}}$

❈ To solve this question we have to use the formula of Newton's 2nd law of motion. But there is a twist and it's the mass is given in grams and the exerted force is in kg-m/s so let's convert g in kg ( Converting ) Now we have to use the formula ( Put the values ) We get our final result very 6 and it's

${\bold{\sf{\underline{Full \: solution}}}}$

☃ Converting g into kg

~ M is 400 g

( We know that 1 kg = 1000 g and 1 g = 1/1000 kg so let's put the values )

↝ M = 400/1000

↝ M = 4/10

↝ M = 2/5

↝ M = 0.4 kg.

☃ Finding a produced by F

↝ F = ma

↝ 12 = 0.4(a)

↝ 12 = 0.4 × a

( ÷ = × ) ; ( × = ÷ )

↝ 12/0.4 = a

↝ 30 = a

↝ a = 30 m/s²

• Henceforth, the acceleration produced by force = 30 m/s²