b) What is the remainder when x^4 + 4x^3+ 2x^2 - 4x + 6 is divided by
(x - 2)?
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Answer:
Let P(x) = x⁴+4x³+2x²-4x+6
By remainder theorem,
if x-2 is dividing then x-2 = 0 = x =2
P(2) = 2⁴+4(2³)+2(2²)-4(2)+6
P(2) = 16+32+8-8+6
P(2) = 54.
hence the remainder is 54.
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