Question

(b.)what will be the loss in mass when 42g of magnesium carbonate is
strongly heated to give magnesium oxide ?​

Answer 1

Answer:

MgCO

3

→MgO+CO

2

Molecular weight of MgCO

3

= 24 + 12 +16 x 3 = 84

Molecular weight of MgO

= 24 + 16 = 40

On heating 84 gms of MgCO

3

the quantity of MgO obtained

= 40 gms

∴ On heating 5 gms of MgCO

3

the quantity of MgO obtained

=

84

40

X5gms

= 2.38 gms

Explanation:

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.

.

.

.

.

Hope it helps you ‼️

Answer 2

Answer:

jay free fire

jay free fire

jay free fire

jay free fire