Question

(b) When a potential difference 1.5 V is applied across a wire of length 0.2m and area of cross section 0.30 mm, a current of 2.4 A flows through the wire. If the number density of free electrons in the wire is 8.4 x 10" ma calculate the average relaxation time.​

Answer 1

Answer:

I=neAv

d

⇒v

d

=

neA

I

=

9×10

28

×1.6×10

−19

×5×10

−6

1.5

=0.02mm/s