Question

B. Which of the following compounds can
NOT demonstrate the law of multiple
proportions ?
a. NO, NO
b. CO, CO2
c. H,O, H,O d. Na S, NaF
2​

Answer 1

Explanation:

Optiondd is rright ondolen explath attion i Aecording to Law of proportions, When two elements combine. to form more them One compound. the mass of one element, unich combines with a fixed mass of the othen element, will alweuys be in simple ratio: ex's it C and O combine two form CORCO2CORCO2 hene, in CO,12CO,12 g of C⇔16gC⇔16g of 0 θθ 190f190f C⇔1.339C⇔1.339 of 0 lnCD2,12gln⁡CD2,12g of C⇔32g&OC⇔32g&O Ox,lggC⇔2.66Ox,lggC⇔2.66 of 0 If is Clear that 1.33:2.66=1:21.33:2.66=1:2 is in simple rretio do, CO2CO2 bmd CO tollows law of multiple proportions. From cubove explatiallion, all the dirst three obtions follow the law low lest Option dd Na2SNa2S, thaf adesn't follow, beeause here three elements ere given Na, B, R. B. IO I cus of multiple proportions is vallid tor two elements.

Answer 2

Your right answer is (a).

OK dear...