Question

(b) Which path is sphery
6. Three identical positive charges Q are arranged at the
vertices of an equilateral triangle. The side of the triangle
is a. Find the intensity of the field at the vertex of a regular
tetrahedron of which the triangle is the base.​

Answer 1

Explanation:

The height of a tetrahedral of side a is

3

2

a

In the given diagram of question,

cosϕ=

3

2

By symmetry, the horizontal components of the charge cancel out.

The vertical component add up,

E=kQ/a

2

×3×cosϕ=3kQ/a

2

×

3

2