B would take three times as long as A and C together C and C twice as long as A+B the three man together complete the work 10days how long would each take saprete
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Step-by-step explanation:
A+B+C =10 days
A+B=2C
A+B+C=2C+C=3C
3C=10 days
C complete work in 30days
C=30 days
A+c=3B
3B+B=4B
4B=10days
B complete work in 40 days
B=40 days
A+B+C can do 1/10 of job in 1day
B can do 1/40 of job in 1 day
C can do 1/30 of job in 1 day
A alone do in 1 day is
1/10-1/40-1/30(12-3-4)/120=5/120=1/24
the time taken by A to complete the job separately is 24/1=24 days
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