Question

b-x-10x^2+8x^3 is exactly divisible by 1-x find the value of b

Answer 1

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p(x) = b-x-10x^2+8x^3
p(x) is completely divisible by 1-x
1-x = 0
-x = -1
x=1

p(1) =0.
putting x =1 in p(x) =0
b - (1) -10(1)^2 +8(1)^3 =0
b-1 - 10 + 8 = 0
b - 11 +8 =0
b- 3 =0.
b= 0+3
b =3

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