Math, asked by shyamal1120, 9 months ago

b/x-c+c/x-b=2. solve the question ​

Answers

Answered by God1OfWholeDarkness
0

Answer:

b/x-c+c/x-b=2

b/x-b-c+c/x

b(1/x-1)+c(1/x-1)=2

(b+x)(1/x-1)=2

(b+x)(1-x)/x=2

(b+x)(1-x)=2x

b+x=2x/(1-x)

b=2x/(1-x)-(x-x^2)/(1-x)

b=(2x-x+x^2)/(1-x)

b-x=x+x^2

b=2x+x^2

b=x(x+2)

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